Find cos B if the angle in triangle ABC is C = 90, BC = 6, AB = 15.
| December 16, 2020 | education
The cosine of an acute angle in a right triangle is found from the division of the adjacent leg to the hypotenuse, that is
cosB = BC / AB
cosB = 6/15 = 2/5 = 0.4
Answer: 0.4
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