Find D (y) and find out if the function is even or odd. f (x) = x³ / 1-cos² x

In order to solve this problem, you need to find D (y) and find out whether the function is even or odd:

1) Find D (y): 1 – cos2x ≠ 0; cos x ≠ ± 1: x ≠ 0, x ≠ π.

2) Let’s check our function for evenness: f (-x) = (-x) ^ 3 / (1 – cos2 (-x)) = – (x ^ 3 / (1 – cos2x)) = -f (x), – hence the function is odd.

Answer: D (y): x ≠ 0, x ≠ π; the function is odd.



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