Find F2 if L1 = 30cm L2 = 15cm F = 30H is known.

Given:

F1 = 30 Newton – force acting on the shoulder L1;

L1 = 30 centimeters = 0.3 meters – shoulder length;

L2 = 15 centimeters = 0.15 meters – the length of the shoulder on which the force F2 acts.

It is required to determine the magnitude of the force F2 (Newton).

Since the problem statement is not specified, we assume that the lever is in equilibrium.

Then:

F1 * L2 = F2 * L2, hence:

F2 = F1 * L1 / L2 = 30 * 0.3 / 0.15 = 9 / 0.15 = 60 Newtons.

Answer: the force F2 is 60 Newtons.