Find out the speed of free fall if the length of the pendulum = 1 number of oscillations = 100
| May 10, 2021 | education
Find out the speed of free fall if the length of the pendulum = 1 number of oscillations = 100, the time of oscillations is 200.
To find out the value of the acceleration due to gravity, we use the equality: t / n = T (oscillation period) = 2 * Π * √ (l / g), whence we express: t2 / (n ^ 2 * 4 * Π ^ 2) = l / g and g = l * n ^ 2 * 4 * Π ^ 2 / t ^ 2.
The values of the variables: l is the length of the pendulum (l = 1 m); n is the number of vibrations (n = 100 vibrations); t is the duration of the oscillations (t = 200 s).
Calculation: g = l * n ^ 2 * 4 * Π ^ 2 / t ^ 2 = 1 * 100 ^ 2 * 4 * 3.14 ^ 2/200 ^ 2 = 9.8596 m / s2.
Answer: The acceleration due to gravity, according to the calculation, has a value of 9.8596 m / s2.
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