Find sinα if cosα = √ 51/10 and α belong to (0; п / 2).
| November 23, 2020 | education
Find from the identity sinx ^ 2 + cosx ^ 2 = 1
sinx = + – √ (1-cosx ^ 2)
sinx = + – √ (1-0.51)
sinx = + – √ 0.49, that is, sinx = 0.7 or -0.7
Since alpha belongs to the range from 0 to pi / 2, then sinx = 0.7
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