Find the 29th term of the arithmetic progression (An) the first term which is – 86 and the difference is 3.

To find the 29th term a29 of this arithmetic sequence, we use the formula for the nth term of the arithmetic progression an = a1 + (n – 1) * d, where a1 is the first term of the arithmetic progression, d is the difference of the arithmetic progression.

By the condition of the problem, the first term a1 of this arithmetic progression is -86, and the difference d of this progression is 3.

Substituting these values, as well as the value n = 29 in the formula for the nth term of the arithmetic progression, we get:

a29 = -86 + (29 – 1) * 3 = -86 + 28 * 3 = -86 + 84 = -2.

Answer: The 29th member of this arithmetic progression is -2.



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