Find the abscissa of the intersection of the graphs of the functions y = 4-4x and y = 6-7x.

A point on the plane has two coordinates x – abscissa, and y – ordinate.

First, let’s determine whether the graphs of the functions y = 4 – 4x and y = 6 – 7x have an intersection point, or if they are parallel. The graphs of the functions y = 4 – 4x and y = 6 – 7x exactly intersect, since their slopes are different (this is the coefficient in front of x: -4 ≠ -7).
The coordinates of the intersection point are suitable for both functions, that is, their coordinates at this point are the same. Therefore, we can equate the right sides of the equations:
4 – 4x = 6 – 7x;

-4x + 7x = 6 – 4;

3x = 2;

x = 2/3 – abscissa (x coordinate) of the intersection point.

Answer: x = 2/3.