Find the abscissa of the point of intersection of the graphs of two linear equations with two variables 4x-3y = 12 and 3x + 4y = -24
If the graphs overlap, then their equations have a common solution. Because it is necessary to find the abscissa, therefore it is necessary to determine at which x the equalities are satisfied:
4x – 3y = 12,
3x + 4y = -24.
From the first equality we find 3y = 4x – 12, y = (4x – 12) / 3.
3x + 4 (4x – 12) / 3 = -24,
3x + (16x – 48) / 3 = -24,
9x + 16x – 48 = -72,
25x = -24,
x = -24/25.
or x = – 0.96.
Answer: the abscissa of the intersection point x = -0.96.
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