Find the abscissa of the point of intersection of the graphs of two linear equations

Find the abscissa of the point of intersection of the graphs of two linear equations with two variables 4x-3y = 12 and 3x + 4y = -24

If the graphs overlap, then their equations have a common solution. Because it is necessary to find the abscissa, therefore it is necessary to determine at which x the equalities are satisfied:

4x – 3y = 12,

3x + 4y = -24.

From the first equality we find 3y = 4x – 12, y = (4x – 12) / 3.

We get:

3x + 4 (4x – 12) / 3 = -24,

3x + (16x – 48) / 3 = -24,

9x + 16x – 48 = -72,

25x = -24,

x = -24/25.

or x = – 0.96.

Answer: the abscissa of the intersection point x = -0.96.