Find the abscissa of the point on the graph of the function y = x ^ 2 + 7x-9, in which the tangent

Find the abscissa of the point on the graph of the function y = x ^ 2 + 7x-9, in which the tangent drawn to this graph is parallel to the straight line y = -5x.

Let’s find the derivative of this function:

y ‘= 2x + 7.

It is equal to the slope of the tangent to the graph of this function at the point with the abscissa x. From the parallelism of the tangent and the straight line y = -5x it follows that

2x + 7 = -5, whence

x = -6.



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