Find the AC side of the ABC triangle if B = 120 ° AB = 6 BC = 10.

The AC side of a given triangle can be found using the following formula:

AC = √ (AB² + BC² – 2 * AB * BC * cos B).

We know all the quantities, it remains to find the length AC. Let’s find it:

AC = √ (6² + 10² – 2 * 6 * 10 * cos 120º) = √ (36 + 100 – 120 * (- 0.5)) = √ (136 + 60) = √186 ≈ 13.6.

Answer: The AC side of triangle ABC is approximately 13.6.



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