Find the acute corners of a right-angled triangle if the hypotenuse and one of the legs is 3√2 and 3.

From the condition we have that the angle B is a straight line. One leg is equal to 3 (AB), hypotenuse is 3√2 (AC).
By the Pythagorean theorem, we find the unknown leg BC.
BC = √AC ^ 2-AB ^ 2
BC = √ ((3√2) ^ 2-3 ^ 2) = √ (9 * 2-9) = √9 = 3
Since the sides and sides are equal, it means that triangle ABC is isosceles.
Hence the base angles are equal.
angle A = angle C = 180-90 / 2 = 45
Answer angle A = 45, angle C = 45