Find the acute corners of a right-angled triangle if the hypotenuse and one of the legs is 3√2 and 3.

univerkov | December 11, 2020 | education

Let ΔABS be rectangular with a right angle A (i.e. ∠A = 90 °)
Hypotenuse BC = 3√2
And let AC = 3
By the Pythagorean theorem: AB = √ ((3√2) ^ 2 – 3 ^ 2) = √ (9 * 2 – 9) = √9 = 3
It turns out that ΔABS is also isosceles. Then ∠В = ∠С = 45 °
Answer: 45 ° and 45 °

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