Find the amount of acceleration that a particle with a mass of 0.1 g with a charge of 4 μC

Find the amount of acceleration that a particle with a mass of 0.1 g with a charge of 4 μC acquires under the action of a uniform electric field with a strength of 1 kV / m? Disregard the force of gravity.

m = 0.1 g = 0.1 * 10-3 kg.

q = 4 μC = 4 * 10-6 Cl.

E = 1 kV / m = 1000 V / m.

a -?

According to 2 Newton’s law, the acceleration of a body, a, is directly proportional to the force F, which acts on the body, and inversely proportional to the mass of the body m: a = F / m.

An electrostatic force F acts on a charged body, the value of which is expressed by the formula: F = q * E, where q is the value of the body’s charge, E is the strength of the electric field.

a = q * E / m.

a = 4 * 10-6 Cl * 1000 V / m / 0.1 * 10-3 kg = 40 m / s2.

Answer: a charged particle will acquire an acceleration a = 40 m / s2.