Find the amount of heat required to vaporize 200 g of water taken at the boiling point.

Find the amount of heat required to vaporize 200 g of water taken at the boiling point. Specific heat of vaporization of water 2.3 * 10 ^ 6 J / kg

The amount of heat required to convert water into steam is calculated by the formula:

Q = L * m, where L is the specific heat of vaporization of water (L = 2.3 * 10 ^ 6 J / kg), m is the mass of water (m = 200 g = 0.2 kg).

Let’s calculate the required amount of heat:

Q = L * m = 2.3 * 10 ^ 6 * 0.2 = 46000 J = 460 kJ.

Answer: To convert 200 g of water into steam, 460 kJ of heat is needed.