Find the amount of heat when the water temperature changes from 30 ° to 100 ° C, if the mass of water is 600g.

Given:

t1 = 30 ° C;

t2 = 100 ° C;

m = 600 g = 0.6 kg;

c = 4200 J / (kg * ° C) – specific heat capacity of water;

Find: Q -?

Decision:

Let’s use the formula to find the amount of heat when heated:

Q = c * m * (t2 – t1) = 4200 * 0.6 * (100 – 30) = 176400 J;

Answer: 176400 J.



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