Find the amount of phosphorus (V) oxide substance obtained by combustion of 0.1 mol of phosphorus in oxygen.

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 moles of phosphorus react with 5 moles of oxygen. In this reaction, 2 moles of phosphorus oxide are synthesized.

We have 0.1 mol of phosphorus.

From this amount of phosphorus, it is possible to synthesize 0.1 / 2 = 0.05 mol of its oxide.

Let’s determine its weight.

To do this, multiply the amount of the substance by its molar weight.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

m P2O5 = 142 x 0.05 = 7.1 grams;