Find the amount of salt and the volume of hydrogen, which was formed by the interaction of 32.5

Find the amount of salt and the volume of hydrogen, which was formed by the interaction of 32.5 grams of zinc with sulfuric acid?

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate (zinc sulfate). The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

The metal reacts with acid in equal molar amounts. During the reaction, the same amounts of salt and hydrogen are synthesized.

Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol; N Zn = 32.5 / 65 = 0.5 mol;

The same amount of hydrogen and zinc sulfate (zinc sulfate) will be synthesized.

Let’s calculate the volume of this amount of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of ideal gas (22.4 liters).

N H2 = 0.5 mol; V H2 = 0.5 x 22.4 = 11.2 liters;