Find the amount of silver substance that is formed when copper is reduced from silver nitrate with a mass of 1.7 g.

By the condition of the problem, we write down the equation and indicate the coefficients:
2AgNO3 + Cu = 2Ag + Cu (NO3) 2 – substitution reaction, silver is released:
Let’s make calculations using the formulas:
M (AgNO3) = 169.8 g / mol;
M (Ag) = 107.8 g / mol;
Y (AgNO3) = m / M = 1.7 / 169.8 = 0.01 mol;
According to the reaction equation, the amount of moles of silver and silver nitrate are equal and are 2 moles, which means that Y (Ag) = 0.01 moles.
Answer: the number of moles of silver is 0.01 mole.