Find the amount of silver substance that is released on a copper plate, placed in 169 g of a 2.5%

| June 9, 2021 | education

Find the amount of silver substance that is released on a copper plate, placed in 169 g of a 2.5% solution of silver nitrate, assuming that all the salt will react.

Find the mass of silver nitrate in the solution.

The mass fraction of a substance is calculated by the formula:

W = m (substance): m (solution) × 100%,

m (substance) = (m (solution) × W): 100%,

m (substance) = (169 g × 2.5%): 100% = 4.3 g.

Let’s find the amount of silver nitrate substance by the formula:

n = m: M.

M (AgNO3) = 108 + 14 + 48 = 170 g / mol.

n = 4.3 g: 170 g / mol = 0.025 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2 AgNO3 + Cu = Cu (NO3) 2 + 2 Ag ↓.

According to the reaction equation, 2 mol of silver nitrate accounts for 2 mol of silver. Substances are in quantitative ratios 1: 1.

The amount of silver nitrate and silver nitrate will be the same.

n (Ag) = 0.025 mol.

Answer: n (Ag) = 0.025 mol.



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