Find the amount of substance of oxygen atoms and phosphorus atoms, which is contained

Find the amount of substance of oxygen atoms and phosphorus atoms, which is contained in phosphorus (III) oxide weighing 220 g.

Given:
m (P2O3) = 220g.
Find: N (P), N (O)

Solution:
1) n (P2O3) = m / M = 220/110 = 2 mol.
2) analysis of the formula of phosphorus (III) oxide shows that n (P) = 2 * n (P2O3), a n (O) = 3 * n (P2O3)
3) n (P) = 2 * 2 = 4 mol
4) n (O) = 3 * 2 = 6 mol

Answer: 4 mol, 6 mol