Find the amount of the substance the volume of chlorine reacted with 8 g of calcium.

univerkov | January 17, 2021 | education

Given:
m (Ca) = 8 g
To find:
n (Cl2)
V (Cl2)
Decision:
Ca + Cl2 = CaCl2
n (Ca) = m / M = 8 g / 40 g / mol = 0.2 mol
n (Ca): n (Cl) = 1: 1
n (Cl2) = 0.2 mol
V (Cl2) = n * Vm = 0.2 mol * 22.4 L / mol = 4.48 L
Answer: 4.48 L

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