Find the angle ABC-isosceles trapezoid ABCD (AB = CD) if it is more than the angle BAD by 14º.

Let’s denote the acute angle at the base of the trapezoid through X0, the angle BAD = X0, then, by condition, the obtuse angle with a smaller base will be equal to (X + 14) 0, angle ABC = (X +14) 0.
The sum of the angles of the trapezoid with its lateral side is 180. Angle ВAD + ABC = 180.
X + X + 14 = 180.
2 * X – 180 – 14 = 166.
X = ВAD = 166/2 = 830.
Angle ABC = 83 + 14 = 970.
Answer: Angle ABC is 970.



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