Find the angle at the base of an isosceles triangle if the angle between the sides is 120 degrees?
| January 25, 2021 | education
An isosceles triangle is a triangle in which the sides are equal:
AB = BC.
In an isosceles triangle, the angles at the base are also equal.
Since the sum of all the angles of the triangle is 180º, and ∠А = ∠С:
∠А = ∠С = (180º – ∠В) / 2;
∠А = ∠С = (180º – 120º) / 2 = 60º / 2 = 30º.
Answer: The angles at the base of the triangle are 30 degrees.
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