Find the angle B, if in the triangle ABC the angle is A = 30 degrees, AC = 2cm, BC = √2cm.

Let’s write the equality for the angles and sides of the triangle, using the data: <A = 30 °, AC = 2cm, BC = √2 cm; <B =?,

AC / sin B = BC / sin A, whence the sought angle sin B = AC * sin A / BC = 2 cm * sin 30 ° / √2 cm = 2 * (1/2) / √2 = 1 / √2 = √2 / 2. Value <B = 45 °.



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