Find the angle B of the triangle ABC, in which AB = √2, BC = √3, angle A = 60 degrees.

sin C / sin A = √2 / √3; sin C = (√2 / √3) * sin A = (√2 / √3) * sin 60 ° = (√2 / √3) * √3 / 2 = √2 / 2. <C = 45 °;

Let’s find the angle <B from the triangle ABC at two other known angles: <B = 180 ° – 60 ° – 45 ° = 75 °.

Answer: <C = 45 °.



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