# Find the angle between the inclined and the plane, if the length of the inclined is 6 cm

Find the angle between the inclined and the plane, if the length of the inclined is 6 cm, and the length of its projection is 3 cm

From point B of inclined AB, we construct a perpendicular BC to the plane α.

The segment АС belongs to the plane α, then ВС is perpendicular to АС.

The segment AC is the projection of the inclined AB on the plane α, according to the condition AC = 3 cm.

In a right-angled triangle ABC, the AC leg is two times shorter than the hypotenuse AB, then the angle ABC = 30.

The sum of the acute angles of a right-angled triangle is 90, then the angle BAC = (90 – 30) = 60.

Answer: The angle between the inclined plane and the plane is 60.

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