Find the angle of an isosceles triangle if one of the angles is 96 degrees.

An isosceles triangle is a triangle in which the sides are equal, as well as the angles at the base are equal.
Since the angles at the base of an isosceles triangle are always sharp (that is, less than 90º), an angle of 96º is the angle ∠B opposite to the base.
Since the sum of all the angles of the triangle is 180º, then:
∠А = ∠С = (180º – ∠В) / 2;
∠А = ∠С = (180º – 96º) / 2 = 84º / 2 = 42º.
Answer: the angles ∠А and ∠С are equal to 42º.