Find the angles of a right-angled triangle if the angle between the bisector and the height

Find the angles of a right-angled triangle if the angle between the bisector and the height drawn from the vertex and the right angle is 15.

Let’s denote a right-angled triangle ABC, angle C – straight line, CH – height, СK – bisector. KСН angle = 15 ° (as required).
Consider a right-angled triangle ВСН, in it the angle Н is a straight line (СН – height), angle ВСН = angle КСВ – angle КСН = 45 ° – 15 ° = 30 °.
Find angle B:
Angle В = 90 ° – angle ВСН = 90 ° – 30 ° = 60 °.
Consider a triangle ABC and find an angle A in it:
Angle A = 90 ° – Angle B = 90 ° – 60 ° = 30 °.
Answer: in triangle ABC the angles are equal: 90 °, 60 °, 30 °.