Find the angles of a triangle if the first of the angles is twice the second and 10 degrees more than the third.

Let the second angle be equal to the variable a.

Therefore, the first angle will be possible to express in the form of 2a, while the last angle can be represented in terms of 2a – 10.

Since we know for sure from the school geometry course that these are the angles of a triangle, which means that their sum is 180 °, then it is possible to write an equation to find out what each angle will be equal to:

a + 2a + 2a – 10 = 180;

5a = 190;

a = 38;

2 * 38 = 76;

76 – 10 = 66.

Answer: The first angle is 76 °, the second is 38 °, and the third is 66 °.