Find the angles of an isosceles trapezoid if one of its angles is 30 degrees greater than the second.

Since, by condition, the trapezoid is isosceles, then its angles at the base are equal.
Angle ВAD = ADС, angle ABC = ВСD.
Let the ВAD angle be X degrees, then the ABC angle will be (X + 30).
In a trapezoid, the sum of the angles at the lateral sides is 1800, then AВD + ABC = X + X + 30 = 180.
2 * X = 180 – 30 = 150.
X = 150/2 = 75.
Angle ВAD = ADС = 75.
Angle ABC = ВСD = 75 + 30 = 105.
Answer: The angles of an isosceles trapezoid are 75 and 105.