Find the angles of an isosceles trapezoid if one of its corners is 30 degrees larger than the other.

In an isosceles trapezoid, the angles at its bases are equal, and the sum of the angles at the lateral side is 180.

Let the acute angle of the trapezoid be X0, then the obtuse angle is (X + 30) 0.

X + X + 30 = 180.

2 * X = 15.

X = 75.

Then the obtuse angle is 75 + 30 = 105.

Answer: The angles of the trapezoid are 75 and 105.



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