Find the angles of an isosceles triangle if one of the angles at the base is a) 50 °; b) 70 °; c) 39 °; d) 83 °

An isosceles triangle is a triangle in which the sides are equal, as well as the angles at the base are equal:

AB = BC;

∠А = ∠С.

Since the sum of all the angles of the triangle is 180º, then:

∠А + ∠В + ∠С = 180º;

∠В = 180º – ∠А – ∠С.

a) ∠В = 180º – 50º – 50º = 80º.

Answer: ∠А = ∠С = 50º; ∠В = 80º.

b) ∠В = 180º – 70º – 70º = 40º.

Answer: ∠А = ∠С = 70º; ∠В = 40º.

c) ∠В = 180º – 39º – 39º = 102º.

Answer: ∠А = ∠С = 39º; ∠В = 102º.

d) ∠В = 180º – 83º – 83º = 14º.

Answer: ∠А = ∠С = 83º; ∠В = 14º.



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