Find the angles of an isosceles triangle if the angle at the base is 60 degrees less than the angle between the sides.

let the angle be between the side. sides x °, then the angle at the base of x is 60 °. the sum of the angles in a triangle is 180 °.
x + 2 (x-60) = 180
x + 2x-120 = 180
3x = 300
x = 100-angle between sides. parties
100-60 = 40 ° base angle
answer: 40 °



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