Find the angles of the quadrilateral ABCD if AB || CD, angle ABC = 138 °, angle CDA = 52 °.
| September 3, 2021 | education
Since, by condition, in the quadrangle ABCD the sides AB and CD are parallel, this quadrilateral is a trapezoid.
In a trapezoid, the sum of the angles at its lateral sides is 180, then:
Angle BAD = (180 – ADC) = (180 – 52) = 128, angle BCD = (180 – CBA) = (180 – 138) = 42.
Answer: The angles of the quadrilateral are 42, 138, 128, 52.
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