Find the angles of the trapezoid abcd if the angle a = 58 ° and the angle d = 100 °.

Because ABСD is a trapezoid, the sum of the angles adjacent to the lateral sides is 180 °.
Then we find the angles B and C
angle B = 180 ° – angle A
angle B = 180 ° – 58 ° = 122 °
angle C = 180 ° – angle D
angle С = 180 ° – 100 ° = 80 °
Answer: 80 °, 122 °.



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