Find the angles of the triangle ABC, if B + angle C = 53, angle A-angle C = 109

The angles of a triangle add up to 180 °.

A + B + C = 180 °;

1) A = 180 ° – (B + C);

B + C = 53 °.

A = 180 ° – 53 °;

A = 127 °.

2) A – C = 109 °;

C = A – 109 °;

C = 127 ° – 109 °;

C = 18 °.

3) B = 180 ° – (A + C);

B = 180 ° – (127 ° + 18 °);

B = 35 °.

Answer: angle A = 127 °, B = 35 °, C = 18 °.



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