Find the angles of triangle ABC if the angle B is 40 degrees greater than the angle A and the angle C

Find the angles of triangle ABC if the angle B is 40 degrees greater than the angle A and the angle C is five times the angle A.

Given:
triangle ABC,
angle B = angle A + 40,
angle C = 5 * angle A,
Find the degree measures of angle A, angle B, angle C -?
Solution:
Consider a triangle ABC. We know that the sum of the degree measures of any triangle is 180 degrees. Let the angle A = x degrees, the angle B = x + 40 degrees, and the angle C = 5 * x degrees. Let’s make the equation:
x + x + 40 + 5 * x = 180;
x + x + 5 * x = 180 – 40;
x + x + 5 * x = 140;
x * (1 + 1 + 5) = 140:
x * 7 = 140;
x = 140: 7;
x = 20 degrees – angle A;
angle B = 20 + 40 = 60 (degrees);
angle C = 5 * 20 = 100 (degrees).
Answer: 20 degrees; 60 degrees; 100 degrees.