Find the angles of triangle AOD where O is the intersection point of the diagonals of the rhombus ABCD angle D = 40 degrees.

Once BD is the diagonal in a rhombus, then the angle D = 80 °. Hence the angle A = C = 100 °. Hence the angle OAD = 50 °. Therefore AOD angle is 180 ° -50 ° -40 ° = 90 °
Answer: 50 °, 90 °



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