Find the Archimedean force in water on a 2x5x10 cm bar when it is half submerged in water.

Fа = g * ẞ (liquids) * V (bodies)
V (body) = 2 * 5 * 10 = 100cm3
Since they were loaded in half, then 100: 2 = 50 cm3 = 0.00005 m3
Density of water = 1000 kg / m3
g≈ 10 N / kg
F = 0.00005m3 * 1000kg / m3 * 10N / kg = 0.5N



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