Find the area and perimeter of a rectangle if its length is 17 dm and its width is 8 dm less than its length.

We will solve this task in steps and explain each of them in detail.
1) 17 – 8 = 9 decimeters – the width of the rectangle, since it is 8 decimeters shorter than the length, and the length is 17 decimeters;
2) 17 * 9 = 153 square decimeters – the area of a rectangle with a length of 17 decimeters and a width of 9 decimeters;
3) 2 * (17 + 9) = 2 * 26 = 52 decimetres – the perimeter of a rectangle with a length of 17 decimeters and a width of 9 decimeters.
Answer: the area is 153 square decimeters; perimeter 52 decimetres.