Find the area and perimeter of a rectangle whose width is 18 centimeters and the length is 6 times greater

1) Calculate the length of the rectangle. The problem says that the length is 6 times the width, which means that to find the length of the rectangle, you need to multiply the width by 6.
Let us denote by the letter a – the length of the rectangle, b – the width.
a = b × 6 = 18 × 6 = 108 cm.
2) Calculate the area of ​​the rectangle. Let’s write a formula for calculating the area of ​​a rectangle:
S = a × b,
Substitute the known values ​​of the length and width into the formula, find the area:
S = 108 × 18 = 1944 cm².
3) Find the perimeter of the rectangle. The perimeter of a rectangle is the sum of the length and width of the rectangle multiplied by 2. Let’s write the formula for the perimeter of a rectangle:
P = (a + b) × 2,
P = (108 + 18) × 2 = 126 × 2 = 252 cm.
Answer: the perimeter of the rectangle is 252 cm, and the area is 1944 cm².



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