Find the area and perimeter of a rectangle whose width is 6 dm, which is 1/4 of its length.

First, we find the length of the rectangle, knowing that it is 1/4 of the width of the rectangle, equal to 6 dm:

6 dm / 1/4 = 24 dm.

Find the area:

S = a * b.

a – the length of the rectangle is 24 dm

b – the width of the rectangle, equal to 6 dm.

S = 24 dm * 6 dm = 144 dm2.

Find the perimeter:

P = a + a + b + b.

P = 24 dm + 24 dm + 6 dm + 6 dm = 60 dm.

Answer: the area is 144 dm2, the perimeter is 60 dm.