Find the area and perimeter of a rectangular sheet of paper if its length is 6 dm and width is 3 dm.

According to the condition of the problem, the length of a given rectangular sheet of paper is 6 dm, and the width of this sheet is 3 dm.

The area of ​​any rectangle is equal to the product of the length and width of this rectangle, therefore, the area S of a given rectangular sheet of paper is:

S = 6 * 3 = 18 dm².

The perimeter of any rectangle is equal to twice the sum of the length and width of this rectangle, therefore, the perimeter P of this rectangular sheet of paper is:

P = 2 * (6 + 3) = 2 * 9 = 18 dm.

Answer: the area of ​​this sheet of paper is 18 dm², the perimeter of this sheet of paper is 18 dm².



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