Find the area and perimeter of a triangle with sides 6 and 8 cm.

1. Given:

1st side of the triangle = 6 cm;

2nd side of the triangle = 8 cm;

3rd side =?

Square – ?

Perimeter -?

2. First, find the third side of the triangle. For this we use the cosine theorem:

Z ^ 2 = √x ^ 2 + y ^ 2 – 2x * y + cosC. The angle is 90 degrees.

X ^ 2 = √36 + 64 – 2 * 6 * 8 + cos 90 = 2;

3. Find the perimeter: P = 6 + 8 + 2 = √16 = 4;

4. Find the area by the formula: √p * (p – a) * (p – b) * (p – c)

S = √4 * (6 – 4) * (8 – 4) * (4 – 2) = √64 = 8.

Answer: 3rd side = 2 cm; perimeter = 4 cm; area = 8 cm.