Find the area of a parallelogram if its two sides are 12 cm and 11 cm and the angle is 30 degrees

1. Vertices of the parallelogram – A, B, C, D. S – area of the parallelogram. ∠А = 30 °. AB = 11 centimeters. AD = 12 centimeters.

2. Draw the height of the BM.

3. We calculate the length of the BM height through the sine ∠BAM, equal to the quotient of the division of BM (leg of a right-angled triangle ABM) by AB (hypotenuse of the indicated triangle):

BM: AB = sine ∠ABM = sine 30 ° = 1/2.

Length of height BM = 11 x 1/2 = 5.5 centimeters.

4. S = AD x BM = 12 x 5.5 = 66 centimeters².

Answer: S equals 66 centimeters².