Find the area of a parallelogram whose sides form an angle of 45 and are equal to 10 cm and 16 cm.

The area of a parallelogram is equal to the product of the lengths of its sides by the sine of the angle between them.

Savsd = AB * AD * Sin45 = 10 * 16 * √2 / 2 = 80 * √2 cm2.

Answer: The area of the parallelogram is 80 * √2 cm2



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