Find the area of a parallelogram with sides of 3 cm and 6 cm, and the angle between them = 30 degrees.

Parallelogram AВСD:
AB = СD = 3 cm
BC = AD = 6 cm
angle BAC = 30 degrees
Consider the triangle ABН:
angle AНВ = 90 degrees
angle ВAН = 30 degrees
BH = 1.5 cm (the leg lying opposite an angle of 30 degrees is equal to half of the hypotenuse)
The area is 6 * 1.5 = 9 cm square.
Answer: 9 cm square.



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