Find the area of a rectangle ABCD if AB = 15 cm CD 3 cm.

Given: ABCD – rectangle;

AB = 15cm, AD = 3cm;

Find: SABCD -? cm ^ 2.

In a rectangle, opposite sides are equal in pairs.

Because from the condition, two sides of a given rectangle are known, then the other two will be respectively equal to each opposite. Thus, AB = DC = 15 cm, AD = BC = 3 cm.

The area of a rectangle is the product of its width and length:

S pr. = A * b, i.e. SABCD = AB * AD = DC * BC = 15 * 3 = 45 (cm ^ 2).

Answer: The area of the rectangle ABCD is 45 cm ^ 2.