Find the area of a rectangle if its length is 28 cm and the perimeter is 132 cm.

Let’s denote by x the width of this rectangle.
According to the condition of the problem, the length of this rectangle is 28 cm, and its perimeter is 132 cm, therefore, the following relation holds:
2 * (x + 28) = 132.
We solve the resulting equation and find the width of this rectangle:
2 * (x + 28) = 132;
x + 28 = 132/2;
x + 28 = 66;
x = 66 – 28;
x = 38.
Find the area S of this rectangle:
S = 28 * 38 = 1064 cm².

Answer: the area of this rectangle is 1064 cm².