Find the area of a rectangle if its perimeter is 110. Find its larger side if it is 1 larger than the smaller side.

Let x be the width,

then the length is x + 1

Since P = 2 * length + 2 * width = 2x + 2 * (x + 1)

Expand the brackets:

2x + 2x + 2 = 110

4x = 108

x = 27 – the width of the rectangle, then the large side and at the same time

length = 27 + 1 = 28

Answer: the large side of the rectangle and the same length of the rectangle is 28.